triangle ABC is a isoceles triangle , and line CD biscects angle ACB.
Given: C is equaldistant from AB.
Prove: CD is the perpendicular bisector of AB
we need to write a two column proof without using PBT or its converse
Full Version: Prove the Perpendicular Bisector Theorem
'<' = "angle"
<A = <CAB
<B = <ABC
<C = <BCA
Prove the following:
m<A + m<B + m<C = 180
m<ACD + m<ABD = m<C
m<ACD + m<A = 90
m<BCD + m<B = 90
m<ADC = 180 - m<A + m<ACD
m<BDC = 180 - m<B + m<BCD
<A = <CAB
<B = <ABC
<C = <BCA
Prove the following:
m<A + m<B + m<C = 180
m<ACD + m<ABD = m<C
m<ACD + m<A = 90
m<BCD + m<B = 90
m<ADC = 180 - m<A + m<ACD
m<BDC = 180 - m<B + m<BCD
that sounds painful
This is a "lo-fi" version of our main content. To view the full version with more information, formatting and images, please click here.