Spaceman3750
Dec 1 2005, 08:09 PM
Here you go myscrnnm. Now shut up.
I figured out Algebraic functions (you know, like f(x)). Yay! I figured out they are exactly like functions in progamming
Herloss
Dec 1 2005, 08:15 PM
Yes, now wait till you figure out functions of functions. ex: f(g(x))
Spaceman3750
Dec 1 2005, 08:16 PM
Already dun that too, had one on the homework assignment tonight. It's all really easy (for me anyway)

.
Mynck
Dec 1 2005, 08:17 PM
public double f(double x) throws ArithmaticException, OutOfDomainException {
return x*x + 6*x + 9;
}
Herloss
Dec 1 2005, 08:19 PM
QUOTE(Spaceman3750 @ Dec 1 2005, 11:16 PM)
Already dun that too, had one on the homework assignment tonight. It's all really easy (for me anyway)

.
It's really easy once you figure out that it's asking you to substitute g(x) for x in f(x). I had to read the chapter three times to figure that out...
Mynck
Dec 1 2005, 08:22 PM
It's really easy for anyone with programming experience
Herloss
Dec 1 2005, 08:23 PM
My programming experience ends with TI-Basic
Spaceman3750
Dec 1 2005, 08:27 PM
My PHP coding experience definitely helped me in understanding functions.
Is it possible to have an algebraic function with two parameters, such as f(x, y) representing somethin like f(x, y) = 2x + 2y? Or am I just being a nerd?
Mynck
Dec 1 2005, 08:30 PM
You're just being a nerd.
Spaceman3750
Dec 1 2005, 08:32 PM
Darnit

. Oh well

.
myscrnnm
Dec 4 2005, 03:26 PM
QUOTE(Spaceman3750 @ Dec 1 2005, 08:09 PM)
Here you go myscrnnm. Now shut up.
I figured out Algebraic functions (you know, like f(x)). Yay! I figured out they are exactly like functions in progamming

What does this have to do with me? Now shut up.
Mynck
Dec 5 2005, 08:08 PM
log0.75 (log9 (log2 8)) = ??
Anonymous
Dec 5 2005, 08:11 PM
QUOTE(Mynck @ Dec 5 2005, 08:08 PM)
log
0.75 (log
9 (log
2 8)) = ??
2.40942
Mynck
Dec 5 2005, 08:25 PM
How about as a radical?
Hmm... what if... S = {x: a / log2 a; a, x is a member of Z}
How many positive members of S are there that are less than 1000?
-----Edit-----
make that distinct members
-----Edit----
What's taking so long?
Mynck
Dec 5 2005, 09:22 PM
Ok... since nobody can figure it out apparently, the answer is
» Click to show Spoiler - click again to hide... «
3
The members of the set are:
2 (a = 2)
2 (a = 4)
4 (a = 16)
64 (a = 256)
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